2.8x^2=116

Solution for 2.8x^2=116 equation:

2.8x^2=116

We move all terms to the left:

2.8x^2-(116)=0

a = 2.8; b = 0; c = -116;
Δ = b2-4ac
Δ = 02-4·2.8·(-116)
Δ = 1299.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1299.2}}{2*2.8}=\frac{0-\sqrt{1299.2}}{5.6}
=-\frac{\sqrt{}}{5.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1299.2}}{2*2.8}=\frac{0+\sqrt{1299.2}}{5.6}
=\frac{\sqrt{}}{5.6}
$